Nimber arithmetic: Difference between revisions
Thundergnat (talk | contribs) →{{header|Raku}}: Less verbose table building code |
→{{header|Wren}}: Slightly nicer output. |
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var fns = [[nimsum, " |
var fns = [[nimsum, "⊕"], [nimprod, "⊗"]] |
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for (fn in fns) { |
for (fn in fns) { |
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System.write(" %(fn[1]) |") |
System.write(" %(fn[1]) |") |
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for (i in 0..15) System.write(Fmt.d(3, i)) |
for (i in 0..15) System.write(Fmt.d(3, i)) |
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System.print("\n--- |
System.print("\n---+%("-" * 48)") |
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for (i in 0..15) { |
for (i in 0..15) { |
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System.write("%(Fmt.d(2, i)) |") |
System.write("%(Fmt.d(2, i)) |") |
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Line 957: | Line 957: | ||
{{out}} |
{{out}} |
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<pre> |
<pre> |
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⊕ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
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--- |
---+------------------------------------------------ |
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0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
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1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 |
1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 |
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Line 976: | Line 976: | ||
15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 |
15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 |
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⊗ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
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--- |
---+------------------------------------------------ |
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0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 |
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1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
Revision as of 14:46, 29 May 2020
The nimbers, also known as Grundy numbers, are the values of the heaps in the game of Nim. They have addition and multiplication operations, unrelated to the addition and multiplication of the integers. Both operations are defined recursively:
The nim-sum of two integers m and n, denoted m⊕n is given by
m⊕n=mex(m'⊕n, m⊕ n' : m'<m, n'<n),
where the mex function returns the smallest integer not in the set. More simply: collect all the nim-sums of m and numbers smaller than n, and all nim-sums of n with all numbers less than m and find the smallest number not in that set. Fortunately, this also turns out to be equal to the bitwise xor of the two.
The nim-product is also defined recursively:
m⊗n=mex([m'⊗n]⊕[m⊗n']⊕[m'⊗n'] : m'<m, n'<n)
The product is more complicated and time-consuming to evaluate, but there are a few facts which may help:
- The operators ⊕ and ⊗ are commutative and distributive
- the nim-product of a Fermat power (22k) and a smaller number is their ordinary product
- the nim-square of a Fermat power x is the ordinary product 3x/2
Tasks:
- Create nimber addition and multiplication tables up to at least 15
- Find the nim-sum and nim-product of two five digit integers of your choice
C
<lang c>#include <stdio.h>
- include <stdint.h>
// highest power of 2 that divides a given number uint32_t hpo2(uint32_t n) {
return n & -n;
}
// base 2 logarithm of the highest power of 2 dividing a given number uint32_t lhpo2(uint32_t n) {
uint32_t q = 0, m = hpo2(n); for (; m % 2 == 0; m >>= 1, ++q) {} return q;
}
// nim-sum of two numbers uint32_t nimsum(uint32_t x, uint32_t y) {
return x ^ y;
}
// nim-product of two numbers uint32_t nimprod(uint32_t x, uint32_t y) {
if (x < 2 || y < 2) return x * y; uint32_t h = hpo2(x); if (x > h) return nimprod(h, y) ^ nimprod(x ^ h, y); if (hpo2(y) < y) return nimprod(y, x); uint32_t xp = lhpo2(x), yp = lhpo2(y); uint32_t comp = xp & yp; if (comp == 0) return x * y; h = hpo2(comp); return nimprod(nimprod(x >> h, y >> h), 3 << (h - 1));
}
void print_table(uint32_t n, char op, uint32_t(*func)(uint32_t, uint32_t)) {
printf(" %c |", op); for (uint32_t a = 0; a <= n; ++a) printf("%3d", a); printf("\n--- -"); for (uint32_t a = 0; a <= n; ++a) printf("---"); printf("\n"); for (uint32_t b = 0; b <= n; ++b) { printf("%2d |", b); for (uint32_t a = 0; a <= n; ++a) printf("%3d", func(a, b)); printf("\n"); }
}
int main() {
print_table(15, '+', nimsum); printf("\n"); print_table(15, '*', nimprod); const uint32_t a = 21508, b = 42689; printf("\n%d + %d = %d\n", a, b, nimsum(a, b)); printf("%d * %d = %d\n", a, b, nimprod(a, b)); return 0;
}</lang>
- Output:
+ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 * | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 21508 + 42689 = 62149 21508 * 42689 = 35202
FreeBASIC
<lang freebasic>function hpo2( n as uinteger ) as uinteger
'highest power of 2 that divides a given number return n and -n
end function
function lhpo2( n as uinteger ) as uinteger
'base 2 logarithm of the highest power of 2 dividing a given number dim as uinteger q = 0, m = hpo2( n ) while m mod 2 = 0 m = m shr 1 q += 1 wend return q
end function
function nimsum(x as uinteger, y as uinteger) as uinteger
'nim-sum of two numbers return x xor y
end function
function nimprod(x as uinteger, y as uinteger) as uinteger
'nim-product of two numbers if x < 2 orelse y < 2 then return x*y dim as uinteger h = hpo2(x) if x > h then return nimprod(h, y) xor nimprod(x xor h, y) 'recursively break x into its powers of 2 if hpo2(y) < y then return nimprod(y, x) 'recursively break y into its powers of 2 by flipping the operands 'now both x and y are powers of two dim as uinteger xp = lhpo2(x), yp = lhpo2(y), comp = xp and yp if comp = 0 then return x*y 'we have no fermat power in common h = hpo2(comp) return nimprod(nimprod(x shr h, y shr h), 3 shl (h - 1)) 'a fermat number square is its sequimultiple
end function
'print tables
function padto( i as ubyte, j as integer ) as string
return wspace(i-len(str(j)))+str(j)
end function
dim as uinteger a, b dim as string outstr
outstr = " + | " for a = 0 to 15
outstr += padto(2, a)+" "
next a print outstr print "--- -------------------------------------------------" for b = 0 to 15
outstr = padto(2, b)+ " | " for a = 0 to 15 outstr += padto(2, nimsum(a,b))+" " next a print outstr
next b print outstr = " * | " for a = 0 to 15
outstr += padto(2, a)+" "
next a print outstr print "--- -------------------------------------------------" for b = 0 to 15
outstr = padto(2, b)+ " | " for a = 0 to 15 outstr += padto(2, nimprod(a,b))+" " next a print outstr
next b print a = 21508 b = 42689
print using "##### + ##### = ##########"; a; b; nimsum(a,b) print using "##### * ##### = ##########"; a; b; nimprod(a,b)</lang>
- Output:
+ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 * | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 21508 + 42689 = 62149 21508 * 42689 = 35202
Go
<lang go>package main
import (
"fmt" "strings"
)
// Highest power of two that divides a given number. func hpo2(n uint) uint { return n & (-n) }
// Base 2 logarithm of the highest power of 2 dividing a given number. func lhpo2(n uint) uint {
q := uint(0) m := hpo2(n) for m%2 == 0 { m = m >> 1 q++ } return q
}
// nim-sum of two numbers. func nimsum(x, y uint) uint { return x ^ y }
// nim-product of two numbers. func nimprod(x, y uint) uint {
if x < 2 || y < 2 { return x * y } h := hpo2(x) if x > h { return nimprod(h, y) ^ nimprod(x^h, y) // break x into powers of 2 } if hpo2(y) < y { return nimprod(y, x) // break y into powers of 2 by flipping operands } xp, yp := lhpo2(x), lhpo2(y) comp := xp & yp if comp == 0 { return x * y // no Fermat power in common } h = hpo2(comp) // a Fermat number square is its sequimultiple return nimprod(nimprod(x>>h, y>>h), 3<<(h-1))
}
type fnop struct {
fn func(x, y uint) uint op string
}
func main() {
for _, f := range []fnop{{nimsum, "+"}, {nimprod, "*"}} { fmt.Printf(" %s |", f.op) for i := 0; i <= 15; i++ { fmt.Printf("%3d", i) } fmt.Println("\n--- " + strings.Repeat("-", 48)) for i := uint(0); i <= 15; i++ { fmt.Printf("%2d |", i) for j := uint(0); j <= 15; j++ { fmt.Printf("%3d", f.fn(i, j)) } fmt.Println() } fmt.Println() }
a := uint(21508) b := uint(42689) fmt.Printf("%d + %d = %d\n", a, b, nimsum(a, b)) fmt.Printf("%d * %d = %d\n", a, b, nimprod(a, b))
}</lang>
- Output:
+ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------ 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 * | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------ 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 21508 + 42689 = 62149 21508 * 42689 = 35202
Julia
<lang julia>""" highest power of 2 that divides a given number """ hpo2(n) = n & -n
""" base 2 logarithm of the highest power of 2 dividing a given number """ lhpo2(n) = begin q, m = 0, hpo2(n); while iseven(m) m >>= 1; q += 1 end; q end
""" nim-sum of two numbers """ nimsum(x, y) = x ⊻ y
""" nim-product of two numbers """ function nimprod(x, y)
(x < 2 || y < 2) && return x * y h = hpo2(x) (x > h) && return nimprod(h, y) ⊻ nimprod(x ⊻ h, y) (hpo2(y) < y) && return nimprod(y, x) xp, yp = lhpo2(x), lhpo2(y) comp = xp & yp comp == 0 && return x * y h = hpo2(comp) return nimprod(nimprod(x >> h, y >> h), 3 << (h - 1))
end
""" print a table of nim-sums or nim-products """ function printtable(n, op)
println(" $op |", prod([lpad(i, 3) for i in 0:n]), "\n--- -", "---"^(n + 1)) for j in 0:n print(lpad(j, 2), " |") for i in 0:n print(lpad(op == '⊕' ? nimsum(i, j) : nimprod(i, j), 3)) end print(j == n ? "\n\n" : "\n") end
end
const a, b = 21508, 42689
printtable(15, '⊕') printtable(15, '⊗') println("nim-sum: $a ⊕ $b = $(nimsum(a, b))") println("nim-product: $a ⊗ $b = $(nimprod(a, b))")
</lang>
- Output:
⊕ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 ⊗ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 nim-sum: 21508 ⊕ 42689 = 62149 nim-product: 21508 ⊗ 42689 = 35202
Phix
<lang Phix>function hpo2(integer n)
-- highest power of 2 that divides a given number return and_bits(n,-n)
end function
function lhpo2(integer n)
-- base 2 logarithm of the highest power of 2 dividing a given number integer q = 0, m = hpo2(n) while remainder(m,2)=0 do m = floor(m/2) q += 1 end while return q
end function
function nimsum(integer x, y)
-- nim-sum of two numbers return xor_bits(x,y)
end function
function nimprod(integer x, y)
-- nim-product of two numbers if x < 2 or y < 2 then return x*y end if integer h = hpo2(x) if x > h then return xor_bits(nimprod(h, y),nimprod(xor_bits(x,h), y)) -- recursively break x into its powers of 2 elsif hpo2(y) < y then return nimprod(y, x) -- recursively break y into its powers of 2 by flipping the operands end if -- now both x and y are powers of two integer xp = lhpo2(x), yp = lhpo2(y), comp = and_bits(xp,yp) if comp = 0 then return x*y end if -- we have no fermat power in common h = hpo2(comp) return nimprod(nimprod(floor(x/power(2,h)), floor(y/power(2,h))), 3*power(2,h-1)) -- a fermat number square is its sequimultiple
end function
procedure print_table(integer n, op)
-- print a table of nim-sums or nim-products printf(1," %c | "&join(repeat("%2d",n+1))&"\n",op&tagset(n,0)) printf(1,"--- -%s\n",repeat('-',(n+1)*3)) for j=0 to n do printf(1,"%2d |",j) for i=0 to n do printf(1,"%3d",iff(op='+' ? nimsum(i, j) : nimprod(i, j))) end for printf(1,"\n") end for printf(1,"\n")
end procedure
print_table(15, '+') print_table(15, '*') constant a = 21508, b = 42689 printf(1,"%5d + %5d = %5d\n",{a,b,nimsum(a,b)}) printf(1,"%5d * %5d = %5d\n",{a,b,nimprod(a,b)})</lang>
- Output:
+ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 * | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 21508 + 42689 = 62149 21508 * 42689 = 35202
Prolog
<lang prolog>% highest power of 2 that divides a given number hpo2(N, P):-
P is N /\ -N.
% base 2 logarithm of the highest power of 2 dividing a given number lhpo2(N, Q):-
hpo2(N, M), lhpo2_(M, 0, Q).
lhpo2_(M, Q, Q):-
1 is M mod 2, !.
lhpo2_(M, Q1, Q):-
M1 is M >> 1, Q2 is Q1 + 1, lhpo2_(M1, Q2, Q).
% nim-sum of two numbers nimsum(X, Y, Sum):-
Sum is X xor Y.
% nim-product of twp numbers nimprod(X, Y, Product):-
(X < 2 ; Y < 2), !, Product is X * Y.
nimprod(X, Y, Product):-
hpo2(X, H), X > H, !, nimprod(H, Y, P1), X1 is X xor H, nimprod(X1, Y, P2), Product is P1 xor P2.
nimprod(X, Y, Product):-
hpo2(Y, H), H < Y, !, nimprod(Y, X, Product).
nimprod(X, Y, Product):-
lhpo2(X, Xp), lhpo2(Y, Yp), Comp is Xp /\ Yp, (Comp == 0 -> Product is X * Y ; hpo2(Comp, H), X1 is X >> H, Y1 is Y >> H, Z is 3 << (H - 1), nimprod(X1, Y1, P), nimprod(P, Z, Product) ).
print_row(N, B, Function):-
writef('%3r |', [B]), Goal =.. [Function, A, B, C], forall(between(0, N, A), (call(Goal), writef('%3r', [C]))), nl.
print_table(N, Operator, Function):-
writef(' %w |', [Operator]), forall(between(0, N, A), writef('%3r', [A])), writef('\n --- -', []), forall(between(0, N, _), writef('---', [])), nl, forall(between(0, N, A), print_row(N, A, Function)).
main:-
print_table(15, '+', nimsum), nl, print_table(15, '*', nimprod), nl, A = 21508, B = 42689, nimsum(A, B, Sum), nimprod(A, B, Product), writef('%w + %w = %w\n', [A, B, Sum]), writef('%w * %w = %w\n', [A, B, Product]).</lang>
- Output:
+ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 * | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 21508 + 42689 = 62149 21508 * 42689 = 35202
Raku
(or at least, heavily inspired by)
<lang perl6>sub infix:<⊕> (Int $x, Int $y) { $x +^ $y }
sub infix:<⊗> (Int $x, Int $y) {
return $x * $y if so $x|$y < 2; my $h = exp $x.lsb, 2; return ($h ⊗ $y) ⊕ (($x ⊕ $h) ⊗ $y) if $x > $h; return ($y ⊗ $x) if (exp $y.lsb, 2) < $y; return $x * $y unless my $comp = $x.lsb +& $y.lsb; $h = exp $comp.lsb, 2; (($x +> $h) ⊗ ($y +> $h)) ⊗ (3 +< ($h - 1))
}
my $upto = 26;
for <⊕>, &infix:<⊕>,
<⊗>, &infix:<⊗> -> $op, &f {
put " $op |", ^$upto .fmt('%3s'), "\n---+", '----' x $upto; -> $r { put $r.fmt('%2s'), ' |', ^$upto .map: { &f($r, $_).fmt('%3s')} } for ^$upto; put "\n";
}
put "21508 ⊕ 42689 = ", 21508 ⊕ 42689; put "21508 ⊗ 42689 = ", 21508 ⊗ 42689;</lang>
- Output:
⊕ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 ---+-------------------------------------------------------------------------------------------------------- 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 17 16 19 18 21 20 23 22 25 24 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 18 19 16 17 22 23 20 21 26 27 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 19 18 17 16 23 22 21 20 27 26 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 20 21 22 23 16 17 18 19 28 29 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 21 20 23 22 17 16 19 18 29 28 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 22 23 20 21 18 19 16 17 30 31 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 23 22 21 20 19 18 17 16 31 30 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 24 25 26 27 28 29 30 31 16 17 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 25 24 27 26 29 28 31 30 17 16 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 26 27 24 25 30 31 28 29 18 19 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 27 26 25 24 31 30 29 28 19 18 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 28 29 30 31 24 25 26 27 20 21 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 29 28 31 30 25 24 27 26 21 20 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 30 31 28 29 26 27 24 25 22 23 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 31 30 29 28 27 26 25 24 23 22 16 | 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 0 1 2 3 4 5 6 7 8 9 17 | 17 16 19 18 21 20 23 22 25 24 27 26 29 28 31 30 1 0 3 2 5 4 7 6 9 8 18 | 18 19 16 17 22 23 20 21 26 27 24 25 30 31 28 29 2 3 0 1 6 7 4 5 10 11 19 | 19 18 17 16 23 22 21 20 27 26 25 24 31 30 29 28 3 2 1 0 7 6 5 4 11 10 20 | 20 21 22 23 16 17 18 19 28 29 30 31 24 25 26 27 4 5 6 7 0 1 2 3 12 13 21 | 21 20 23 22 17 16 19 18 29 28 31 30 25 24 27 26 5 4 7 6 1 0 3 2 13 12 22 | 22 23 20 21 18 19 16 17 30 31 28 29 26 27 24 25 6 7 4 5 2 3 0 1 14 15 23 | 23 22 21 20 19 18 17 16 31 30 29 28 27 26 25 24 7 6 5 4 3 2 1 0 15 14 24 | 24 25 26 27 28 29 30 31 16 17 18 19 20 21 22 23 8 9 10 11 12 13 14 15 0 1 25 | 25 24 27 26 29 28 31 30 17 16 19 18 21 20 23 22 9 8 11 10 13 12 15 14 1 0 ⊗ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 ---+-------------------------------------------------------------------------------------------------------- 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 32 34 35 33 40 42 43 41 44 46 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 48 51 49 50 60 63 61 62 52 55 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 64 68 72 76 70 66 78 74 75 79 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 80 85 90 95 82 87 88 93 83 86 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 96 102 107 109 110 104 101 99 103 97 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 112 119 121 126 122 125 115 116 127 120 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 128 136 140 132 139 131 135 143 141 133 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 144 153 158 151 159 150 145 152 149 156 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 160 170 175 165 163 169 172 166 161 171 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 176 187 189 182 183 188 186 177 185 178 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 192 204 196 200 205 193 201 197 198 202 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 208 221 214 219 217 212 223 210 222 211 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 224 238 231 233 229 235 226 236 234 228 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 240 255 245 250 241 254 244 251 242 253 16 | 0 16 32 48 64 80 96 112 128 144 160 176 192 208 224 240 24 8 56 40 88 72 120 104 152 136 17 | 0 17 34 51 68 85 102 119 136 153 170 187 204 221 238 255 8 25 42 59 76 93 110 127 128 145 18 | 0 18 35 49 72 90 107 121 140 158 175 189 196 214 231 245 56 42 27 9 112 98 83 65 180 166 19 | 0 19 33 50 76 95 109 126 132 151 165 182 200 219 233 250 40 59 9 26 100 119 69 86 172 191 20 | 0 20 40 60 70 82 110 122 139 159 163 183 205 217 229 241 88 76 112 100 30 10 54 34 211 199 21 | 0 21 42 63 66 87 104 125 131 150 169 188 193 212 235 254 72 93 98 119 10 31 32 53 203 222 22 | 0 22 43 61 78 88 101 115 135 145 172 186 201 223 226 244 120 110 83 69 54 32 29 11 255 233 23 | 0 23 41 62 74 93 99 116 143 152 166 177 197 210 236 251 104 127 65 86 34 53 11 28 231 240 24 | 0 24 44 52 75 83 103 127 141 149 161 185 198 222 234 242 152 128 180 172 211 203 255 231 21 13 25 | 0 25 46 55 79 86 97 120 133 156 171 178 202 211 228 253 136 145 166 191 199 222 233 240 13 20 21508 ⊕ 42689 = 62149 21508 ⊗ 42689 = 35202
Rust
<lang rust>// highest power of 2 that divides a given number fn hpo2(n : u32) -> u32 {
n & (0xFFFFFFFF - n + 1)
}
// base 2 logarithm of the highest power of 2 dividing a given number fn lhpo2(n : u32) -> u32 {
let mut q : u32 = 0; let mut m : u32 = hpo2(n); while m % 2 == 0 { m >>= 1; q += 1; } q
}
// nim-sum of two numbers fn nimsum(x : u32, y : u32) -> u32 {
x ^ y
}
// nim-product of two numbers fn nimprod(x : u32, y : u32) -> u32 {
if x < 2 || y < 2 { return x * y; } let mut h : u32 = hpo2(x); if x > h { return nimprod(h, y) ^ nimprod(x ^ h, y); } if hpo2(y) < y { return nimprod(y, x); } let xp : u32 = lhpo2(x); let yp : u32 = lhpo2(y); let comp : u32 = xp & yp; if comp == 0 { return x * y; } h = hpo2(comp); nimprod(nimprod(x >> h, y >> h), 3 << (h - 1))
}
fn print_table(n : u32, op : char, func : fn(u32, u32) -> u32) {
print!(" {} |", op); for a in 0..=n { print!("{:3}", a); } print!("\n--- -"); for _ in 0..=n { print!("---"); } println!(); for b in 0..=n { print!("{:2} |", b); for a in 0..=n { print!("{:3}", func(a, b)); } println!(); }
}
fn main() {
print_table(15, '+', nimsum); println!(); print_table(15, '*', nimprod); let a : u32 = 21508; let b : u32 = 42689; println!("\n{} + {} = {}", a, b, nimsum(a, b)); println!("{} * {} = {}", a, b, nimprod(a, b));
}</lang>
- Output:
+ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 * | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 --- ------------------------------------------------- 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 21508 + 42689 = 62149 21508 * 42689 = 35202
Wren
<lang ecmascript>import "/fmt" for Fmt
// Highest power of two that divides a given number. var hpo2 = Fn.new { |n| n & (-n) }
// Base 2 logarithm of the highest power of 2 dividing a given number. var lhpo2 = Fn.new { |n|
var q = 0 var m = hpo2.call(n) while (m%2 == 0) { m = m >> 1 q = q + 1 } return q
}
// nim-sum of two numbers. var nimsum = Fn.new { |x, y| x ^ y }
// nim-product of two numbers. var nimprod // recursive nimprod = Fn.new { |x, y|
if (x < 2 || y < 2) return x * y var h = hpo2.call(x) System.write("") // fixes VM recursion bug if (x > h) return nimprod.call(h, y) ^ nimprod.call(x ^ h, y) // break x into powers of 2 if (hpo2.call(y) < y) return nimprod.call(y, x) // break y into powers of 2 var xp = lhpo2.call(x) var yp = lhpo2.call(y) var comp = xp & yp if (comp == 0) return x * y // no Fermat power in common h = hpo2.call(comp) // a Fermat number square is its sequimultiple return nimprod.call(nimprod.call(x >> h, y >> h), 3 << (h-1))
}
var fns = [[nimsum, "⊕"], [nimprod, "⊗"]] for (fn in fns) {
System.write(" %(fn[1]) |") for (i in 0..15) System.write(Fmt.d(3, i)) System.print("\n---+%("-" * 48)") for (i in 0..15) { System.write("%(Fmt.d(2, i)) |") for (j in 0..15) System.write(Fmt.d(3, fn[0].call(i, j))) System.print() } System.print()
} var a = 21508 var b = 42689 System.print("%(a) + %(b) = %(nimsum.call(a, b))") System.print("%(a) * %(b) = %(nimprod.call(a, b))")</lang>
- Output:
⊕ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ---+------------------------------------------------ 0 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1 | 1 0 3 2 5 4 7 6 9 8 11 10 13 12 15 14 2 | 2 3 0 1 6 7 4 5 10 11 8 9 14 15 12 13 3 | 3 2 1 0 7 6 5 4 11 10 9 8 15 14 13 12 4 | 4 5 6 7 0 1 2 3 12 13 14 15 8 9 10 11 5 | 5 4 7 6 1 0 3 2 13 12 15 14 9 8 11 10 6 | 6 7 4 5 2 3 0 1 14 15 12 13 10 11 8 9 7 | 7 6 5 4 3 2 1 0 15 14 13 12 11 10 9 8 8 | 8 9 10 11 12 13 14 15 0 1 2 3 4 5 6 7 9 | 9 8 11 10 13 12 15 14 1 0 3 2 5 4 7 6 10 | 10 11 8 9 14 15 12 13 2 3 0 1 6 7 4 5 11 | 11 10 9 8 15 14 13 12 3 2 1 0 7 6 5 4 12 | 12 13 14 15 8 9 10 11 4 5 6 7 0 1 2 3 13 | 13 12 15 14 9 8 11 10 5 4 7 6 1 0 3 2 14 | 14 15 12 13 10 11 8 9 6 7 4 5 2 3 0 1 15 | 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 ⊗ | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ---+------------------------------------------------ 0 | 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 2 | 0 2 3 1 8 10 11 9 12 14 15 13 4 6 7 5 3 | 0 3 1 2 12 15 13 14 4 7 5 6 8 11 9 10 4 | 0 4 8 12 6 2 14 10 11 15 3 7 13 9 5 1 5 | 0 5 10 15 2 7 8 13 3 6 9 12 1 4 11 14 6 | 0 6 11 13 14 8 5 3 7 1 12 10 9 15 2 4 7 | 0 7 9 14 10 13 3 4 15 8 6 1 5 2 12 11 8 | 0 8 12 4 11 3 7 15 13 5 1 9 6 14 10 2 9 | 0 9 14 7 15 6 1 8 5 12 11 2 10 3 4 13 10 | 0 10 15 5 3 9 12 6 1 11 14 4 2 8 13 7 11 | 0 11 13 6 7 12 10 1 9 2 4 15 14 5 3 8 12 | 0 12 4 8 13 1 9 5 6 10 2 14 11 7 15 3 13 | 0 13 6 11 9 4 15 2 14 3 8 5 7 10 1 12 14 | 0 14 7 9 5 11 2 12 10 4 13 3 15 1 8 6 15 | 0 15 5 10 1 14 4 11 2 13 7 8 3 12 6 9 21508 + 42689 = 62149 21508 * 42689 = 35202