Sierpinski pentagon: Difference between revisions
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=={{header|C}}== |
=={{header|C}}== |
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The Sierpinski fractals can be generated via the [http://mathworld.wolfram.com/ChaosGame.html Chaos Game]. This implementation thus generalizes the [[Chaos game]] C implementation on Rosettacode. As the number of sides increases, the number of iterations must increase dramatically for a well pronounced fractal ( 30000 for a pentagon). Requires the [http://www.cs.colorado.edu/~main/bgi/cs1300/ WinBGIm] library. |
The Sierpinski fractals can be generated via the [http://mathworld.wolfram.com/ChaosGame.html Chaos Game]. This implementation thus generalizes the [[Chaos game]] C implementation on Rosettacode. As the number of sides increases, the number of iterations must increase dramatically for a well pronounced fractal ( 30000 for a pentagon). This is in keeping with the requirements that the implementation should work for polygons with sides 1 to 4 as well. Requires the [http://www.cs.colorado.edu/~main/bgi/cs1300/ WinBGIm] library. |
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<lang C> |
<lang C> |
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/*Abhishek Ghosh, 24th September 2017*/ |
/*Abhishek Ghosh, 24th September 2017*/ |
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</lang> |
</lang> |
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=={{header|Haskell}}== |
=={{header|Haskell}}== |
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For universal solution see [[Fractal tree#Haskell]] |
For universal solution see [[Fractal tree#Haskell]] |
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Revision as of 08:06, 24 September 2017
You are encouraged to solve this task according to the task description, using any language you may know.
Produce a graphical or ASCII-art representation of a Sierpinski pentagon (aka a Pentaflake) of order 5. Your code should also be able to correctly generate representations of lower orders: 1 to 4.
- See also
C
The Sierpinski fractals can be generated via the Chaos Game. This implementation thus generalizes the Chaos game C implementation on Rosettacode. As the number of sides increases, the number of iterations must increase dramatically for a well pronounced fractal ( 30000 for a pentagon). This is in keeping with the requirements that the implementation should work for polygons with sides 1 to 4 as well. Requires the WinBGIm library. <lang C> /*Abhishek Ghosh, 24th September 2017*/
- include<graphics.h>
- include<stdlib.h>
- include<stdio.h>
- include<math.h>
- include<time.h>
- define pi M_PI
int main(){
time_t t; double side, **vertices,seedX,seedY,windowSide = 500,sumX=0,sumY=0; int i,iter,choice,numSides;
printf("Enter number of sides : "); scanf("%d",&numSides);
printf("Enter polygon side length : "); scanf("%lf",&side);
printf("Enter number of iterations : "); scanf("%d",&iter);
initwindow(windowSide,windowSide,"Polygon Chaos");
vertices = (double**)malloc(numSides*sizeof(double*));
for(i=0;i<numSides;i++){ vertices[i] = (double*)malloc(2 * sizeof(double));
vertices[i][0] = windowSide/2 + side*cos(i*2*pi/numSides); vertices[i][1] = windowSide/2 + side*sin(i*2*pi/numSides); sumX+= vertices[i][0]; sumY+= vertices[i][1]; putpixel(vertices[i][0],vertices[i][1],15); }
srand((unsigned)time(&t));
seedX = sumX/numSides; seedY = sumY/numSides;
putpixel(seedX,seedY,15);
for(i=0;i<iter;i++){ choice = rand()%numSides;
seedX = (seedX + (numSides-2)*vertices[choice][0])/(numSides-1); seedY = (seedY + (numSides-2)*vertices[choice][1])/(numSides-1);
putpixel(seedX,seedY,15); }
free(vertices);
getch();
closegraph();
return 0; } </lang>
Haskell
For universal solution see Fractal tree#Haskell
<lang haskell>import Graphics.Gloss
pentaflake :: Int -> Picture pentaflake order = iterate transformation pentagon !! order
where transformation = Scale s s . foldMap copy [0,72..288] copy a = Rotate a . Translate 0 x pentagon = Polygon [ (sin a, cos a) | a <- [0,2*pi/5..2*pi] ] x = 2*cos(pi/5) s = 1/(1+x)
main = display dc white (Color blue $ Scale 300 300 $ pentaflake 5)
where dc = InWindow "Pentaflake" (400, 400) (0, 0)</lang>
Explanation: Since Picture forms a monoid with image overlaying as multiplication, so do functions having type Picture -> Picture:
f,g :: Picture -> Picture f <> g = \p -> f p <> g p
Function copy for an angle returns transformation, which shifts and rotates given picture, therefore foldMap copy for a list of angles returns a transformation, which shifts and rotates initial image five times. After that the resulting image is scaled to fit the inital size, so that it is ready for next iteration.
If one wants to get all intermediate pentaflakes transformation shoud be changed as follows:
<lang haskell>transformation = Scale s s . (Rotate 36 <> foldMap copy [0,72..288])</lang>
See also the implementation using Diagrams
Java
<lang java>import java.awt.*; import java.awt.event.ActionEvent; import java.awt.geom.Path2D; import static java.lang.Math.*; import java.util.Random; import javax.swing.*;
public class SierpinskiPentagon extends JPanel {
// exterior angle final double degrees072 = toRadians(72);
/* After scaling we'll have 2 sides plus a gap occupying the length
of a side before scaling. The gap is the base of an isosceles triangle
with a base angle of 72 degrees. */
final double scaleFactor = 1 / (2 + cos(degrees072) * 2);
final int margin = 20; int limit = 0; Random r = new Random();
public SierpinskiPentagon() {
setPreferredSize(new Dimension(640, 640));
setBackground(Color.white);
new Timer(3000, (ActionEvent e) -> {
limit++;
if (limit >= 5)
limit = 0;
repaint();
}).start();
}
void drawPentagon(Graphics2D g, double x, double y, double side, int depth) {
double angle = 3 * degrees072; // starting angle
if (depth == 0) {
Path2D p = new Path2D.Double();
p.moveTo(x, y);
// draw from the top
for (int i = 0; i < 5; i++) {
x = x + cos(angle) * side;
y = y - sin(angle) * side;
p.lineTo(x, y);
angle += degrees072;
}
g.setColor(RandomHue.next());
g.fill(p);
} else {
side *= scaleFactor;
/* Starting at the top of the highest pentagon, calculate
the top vertices of the other pentagons by taking the
length of the scaled side plus the length of the gap. */
double distance = side + side * cos(degrees072) * 2;
/* The top positions form a virtual pentagon of their own,
so simply move from one to the other by changing direction. */
for (int i = 0; i < 5; i++) {
x = x + cos(angle) * distance;
y = y - sin(angle) * distance;
drawPentagon(g, x, y, side, depth - 1);
angle += degrees072;
}
}
}
@Override
public void paintComponent(Graphics gg) {
super.paintComponent(gg);
Graphics2D g = (Graphics2D) gg;
g.setRenderingHint(RenderingHints.KEY_ANTIALIASING,
RenderingHints.VALUE_ANTIALIAS_ON);
int w = getWidth();
double radius = w / 2 - 2 * margin;
double side = radius * sin(PI / 5) * 2;
drawPentagon(g, w / 2, 3 * margin, side, limit); }
public static void main(String[] args) {
SwingUtilities.invokeLater(() -> {
JFrame f = new JFrame();
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
f.setTitle("Sierpinski Pentagon");
f.setResizable(true);
f.add(new SierpinskiPentagon(), BorderLayout.CENTER);
f.pack();
f.setLocationRelativeTo(null);
f.setVisible(true);
});
}
}
class RandomHue {
/* Try to avoid random color values clumping together */ final static double goldenRatioConjugate = (sqrt(5) - 1) / 2; private static double hue = Math.random();
static Color next() {
hue = (hue + goldenRatioConjugate) % 1;
return Color.getHSBColor((float) hue, 1, 1);
}
}</lang>
JavaScript
- Notes
- I didn't try to, but got the first of 2 possible versions according to WP N-flake article. Mine has central pentagon. All others here got second version.
- This one looks a little bit differently from the 1st version on WP. Almost like 2nd version, but with central pentagon.
- Not a Durer's pentagon either.
<lang html>
<html>
<head>
<script type="application/x-javascript">
// Globals
var cvs, ctx, scale=500, p0, ord=0, clr='blue', jc=0;
var clrs=['blue','navy','green','darkgreen','red','brown','yellow','cyan'];
function p5f() {
cvs = document.getElementById("cvsid");
ctx = cvs.getContext("2d");
cvs.onclick=iter;
pInit(); //init plot
}
function iter() {
if(ord>5) {resetf(0)};
ctx.clearRect(0,0,cvs.width,cvs.height);
p0.forEach(iter5);
p0.forEach(pIter5);
ord++; document.getElementById("p1id").innerHTML=ord;
}
function iter5(v, i, a) {
if(typeof(v[0][0]) == "object") {a[i].forEach(iter5)}
else {a[i] = meta5(v)}
}
function pIter5(v, i, a) {
if(typeof(v[0][0]) == "object") {v.forEach(pIter5)}
else {pPoly(v)}
}
function pInit() {
p0 = [make5([.5,.5], .5)]; pPoly(p0[0]);
}
function meta5(h) {
c=h[0]; p1=c; p2=h[1]; z1=p1[0]-p2[0]; z2=p1[1]-p2[1];
dist = Math.sqrt(z1*z1 + z2*z2)/2.65;
nP=[];
for(k=1; k<h.length; k++) {
p1=h[k]; p2=c; a=Math.atan2(p2[1]-p1[1], p2[0]-p1[0]);
nP[k] = make5(ppad(a, dist, h[k]), dist)
}
nP[0]=make5(c, dist);
return nP;
}
function make5(c, r) {
vs=[]; j = 1;
for(i=1/10; i<2; i+=2/5) {
vs[j]=ppad(i*Math.PI, r, c); j++;
}
vs[0] = c; return vs;
}
function pPoly(s) {
ctx.beginPath(); ctx.moveTo(s[1][0]*scale, s[1][1]*-scale+scale); for(i=2; i<s.length; i++) ctx.lineTo(s[i][0]*scale, s[i][1]*-scale+scale); ctx.fillStyle=clr; ctx.fill()
}
// a - angle, d - distance, p - point function ppad(a, d, p) {
x=p[0]; y=p[1]; x2=d*Math.cos(a)+x; y2=d*Math.sin(a)+y; return [x2,y2]
}
function resetf(rord) {
ctx.clearRect(0,0,cvs.width,cvs.height);
ord=rord; jc++; if(jc>7){jc=0}; clr=clrs[jc];
document.getElementById("p1id").innerHTML=ord;
p5f();
} </script> </head>
<body onload="p5f()" style="font-family: arial, helvatica, sans-serif;"> Click Pentaflake to iterate. Order: <label id='p1id'>0</label> <input type="submit" value="RESET" onclick="resetf(0);"> (Reset anytime: to start new Pentaflake and change color.)
<canvas id="cvsid" width=640 height=640></canvas> </body>
</html> </lang>
- Output:
Page with Pentaflakejs.png Clicking Pentaflake you can see orders 1-6 of it in different colors.
Kotlin
<lang scala>// version 1.1.2
import java.awt.* import java.awt.geom.Path2D import java.util.Random import javax.swing.*
class SierpinskiPentagon : JPanel() {
// exterior angle private val degrees072 = Math.toRadians(72.0)
/* After scaling we'll have 2 sides plus a gap occupying the length
of a side before scaling. The gap is the base of an isosceles triangle
with a base angle of 72 degrees. */
private val scaleFactor = 1.0 / (2.0 + Math.cos(degrees072) * 2.0)
private val margin = 20 private var limit = 0 private val r = Random()
init {
preferredSize = Dimension(640, 640)
background = Color.white
Timer(3000) {
limit++
if (limit >= 5) limit = 0
repaint()
}.start()
}
private fun drawPentagon(g: Graphics2D, x: Double, y: Double, s: Double, depth: Int) {
var angle = 3.0 * degrees072 // starting angle
var xx = x
var yy = y
var side = s
if (depth == 0) {
val p = Path2D.Double()
p.moveTo(xx, yy)
// draw from the top
for (i in 0 until 5) {
xx += Math.cos(angle) * side
yy -= Math.sin(angle) * side
p.lineTo(xx, yy)
angle += degrees072
}
g.color = RandomHue.next()
g.fill(p)
}
else {
side *= scaleFactor
/* Starting at the top of the highest pentagon, calculate
the top vertices of the other pentagons by taking the
length of the scaled side plus the length of the gap. */
val distance = side + side * Math.cos(degrees072) * 2.0
/* The top positions form a virtual pentagon of their own,
so simply move from one to the other by changing direction. */
for (i in 0 until 5) {
xx += Math.cos(angle) * distance
yy -= Math.sin(angle) * distance
drawPentagon(g, xx, yy, side, depth - 1)
angle += degrees072
}
}
}
override fun paintComponent(gg: Graphics) {
super.paintComponent(gg)
val g = gg as Graphics2D
g.setRenderingHint(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON)
val hw = width / 2
val radius = hw - 2.0 * margin
val side = radius * Math.sin(Math.PI / 5.0) * 2.0
drawPentagon(g, hw.toDouble(), 3.0 * margin, side, limit)
}
private class RandomHue {
/* Try to avoid random color values clumping together */
companion object {
val goldenRatioConjugate = (Math.sqrt(5.0) - 1.0) / 2.0
var hue = Math.random()
fun next(): Color {
hue = (hue + goldenRatioConjugate) % 1
return Color.getHSBColor(hue.toFloat(), 1.0f, 1.0f)
}
}
}
}
fun main(args: Array<String>) {
SwingUtilities.invokeLater {
val f = JFrame()
f.defaultCloseOperation = JFrame.EXIT_ON_CLOSE
f.title = "Sierpinski Pentagon"
f.isResizable = true
f.add(SierpinskiPentagon(), BorderLayout.CENTER)
f.pack()
f.setLocationRelativeTo(null)
f.isVisible = true
}
}</lang>
Mathematica
<lang mathematica>pentaFlake[0] = RegularPolygon[5]; pentaFlake[n_] :=
GeometricTransformation[pentaFlake[n - 1],
TranslationTransform /@
CirclePoints[{GoldenRatio^(2 n - 1), Pi/10}, 5]]
Graphics@pentaFlake[4]</lang>
- Output:
https://i.imgur.com/rvXvQc0.png
MATLAB
<lang MATLAB>[x, x0] = deal(exp(1i*(0.5:.4:2.1)*pi)); for k = 1 : 4
x = x(:) + x0 * (1 + sqrt(5)) * (3 + sqrt(5)) ^(k - 1) / 2 ^ k;
end patch('Faces', reshape(1 : 5 * 5 ^ k, 5, )', 'Vertices', [real(x(:)) imag(x(:))]) axis image off</lang>
- Output:
http://i.imgur.com/8ht6HqG.png
Perl 6
Generate an SVG file to STDOUT. Redirect to a file to capture and display it. <lang perl6>constant order = 5; constant $dim = 250; constant $sides = 5; constant scaling-factor = ( 3 - 5**.5 ) / 2; my @orders = ((1 - scaling-factor) * $dim) «*» scaling-factor «**» (^order);
INIT say qq:to/STOP/;
<?xml version="1.0" standalone="no"?> <!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 1.1//EN" "http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd"> <svg height="{$dim*2}" width="{$dim*2}" style="fill:blue" transform="translate($dim,$dim) rotate(-18)" version="1.1" xmlns="http://www.w3.org/2000/svg"> STOP
END say '</svg>';
my @vertices = map { cis( $_ * τ / $sides ) }, ^$sides;
for 0 ..^ $sides ** order -> $i {
my $vector = [+] @vertices[$i.base($sides).fmt("%{order}d").comb] «*» @orders;
say pgon ((@orders[*-1] * (1 - scaling-factor)) «*» @vertices «+» $vector)».reals».fmt("%0.3f");
};
sub pgon (@q) { qq|<polygon points="{@q}"/>| } </lang>
Python
Draws the result on a canvas. Runs pretty slowly.
<lang python>from turtle import * import math speed(0) # 0 is the fastest speed. Otherwise, 1 (slow) to 10 (fast) hideturtle() # hide the default turtle
part_ratio = 2 * math.cos(math.radians(72)) side_ratio = 1 / (part_ratio + 2)
hide_turtles = True # show/hide turtles as they draw path_color = "black" # path color fill_color = "black" # fill color
- turtle, size
def pentagon(t, s):
t.color(path_color, fill_color) t.pendown() t.right(36) t.begin_fill() for i in range(5): t.forward(s) t.right(72) t.end_fill()
- iteration, turtle, size
def sierpinski(i, t, s):
t.setheading(0)
new_size = s * side_ratio
if i > 1:
i -= 1
# create four more turtles
for j in range(4):
t.right(36)
short = s * side_ratio / part_ratio
dist = [short, s, s, short][j]
# spawn a turtle
spawn = Turtle()
if hide_turtles:spawn.hideturtle()
spawn.penup()
spawn.setposition(t.position())
spawn.setheading(t.heading())
spawn.forward(dist)
# recurse for spawned turtles
sierpinski(i, spawn, new_size)
# recurse for parent turtle
sierpinski(i, t, new_size)
else:
# draw a pentagon
pentagon(t, s)
# delete turtle
del t
def main():
t = Turtle() t.hideturtle() t.penup() screen = t.getscreen() y = screen.window_height() t.goto(0, y/2-20) i = 5 # depth. i >= 1 size = 300 # side length # so the spawned turtles move only the distance to an inner pentagon size *= part_ratio # begin recursion sierpinski(i, t, size)
main()</lang>
See online implementation. See completed output.
Racket
<lang racket>#lang racket/base (require racket/draw pict racket/math racket/class)
- exterior angle
(define 72-degrees (degrees->radians 72))
- After scaling we'll have 2 sides plus a gap occupying the length
- of a side before scaling. The gap is the base of an isosceles triangle
- with a base angle of 72 degrees.
(define scale-factor (/ (+ 2 (* (cos 72-degrees) 2))))
- Starting at the top of the highest pentagon, calculate
- the top vertices of the other pentagons by taking the
- length of the scaled side plus the length of the gap.
(define dist-factor (+ 1 (* (cos 72-degrees) 2)))
- don't use scale, since it scales brushes too (making lines all tiny)
(define (draw-pentagon x y side depth dc)
(let recur ((x x) (y y) (side side) (depth depth))
(cond
[(zero? depth)
(define p (new dc-path%))
(send p move-to x y)
(for/fold ((x x) (y y) (α (* 3 72-degrees))) ((i 5))
(send p line-to x y)
(values (+ x (* side (cos α)))
(- y (* side (sin α)))
(+ α 72-degrees)))
(send p close)
(send dc draw-path p)]
[else
(define side/ (* side scale-factor))
(define dist (* side/ dist-factor))
;; The top positions form a virtual pentagon of their own,
;; so simply move from one to the other by changing direction.
(for/fold ((x x) (y y) (α (* 3 72-degrees))) ((i 5))
(recur x y side/ (sub1 depth))
(values (+ x (* dist (cos α)))
(- y (* dist (sin α)))
(+ α 72-degrees)))])))
(define (dc-draw-pentagon depth w h #:margin (margin 4))
(dc (lambda (dc dx dy)
(define old-brush (send dc get-brush))
(send dc set-brush (make-brush #:style 'transparent))
(draw-pentagon (/ w 2)
(* 3 margin)
(* (- (/ w 2) (* 2 margin))
(sin (/ pi 5)) 2)
depth
dc)
(send dc set-brush old-brush))
w h))
(dc-draw-pentagon 1 120 120) (dc-draw-pentagon 2 120 120) (dc-draw-pentagon 3 120 120) (dc-draw-pentagon 4 120 120) (dc-draw-pentagon 5 640 640)</lang>
Sidef
Generates a SVG image to STDOUT. Redirect to a file to capture and display it. <lang ruby>define order = 5 define sides = 5 define dim = 500 define scaling_factor = ((3 - 5**0.5) / 2) var orders = order.of {|i| ((1-scaling_factor) * dim) * scaling_factor**i }
say <<"STOP"; <?xml version="1.0" standalone="no"?> <!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 1.1//EN"
"http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd">
<svg height="#{dim*2}" width="#{dim*2}"
style="fill:blue" transform="translate(#{dim},#{dim}) rotate(-18)"
version="1.1" xmlns="http://www.w3.org/2000/svg">
STOP
var vertices = sides.of {|i| Complex(0, i * Number.tau / sides).exp }
for i in ^(sides**order) {
var vector = ([vertices["%#{order}d" % i.base(sides) -> chars]] »*« orders «+»)
var points = (vertices »*» orders[-1]*(1-scaling_factor) »+» vector »reals()» «%« '%0.3f')
say ('<polygon points="' + points.join(' ') + '"/>')
} say '</svg>'</lang>
zkl
<lang zkl>const order=5, sides=5, dim=250, scaleFactor=((3.0 - (5.0).pow(0.5))/2); const tau=(0.0).pi*2; // 2*pi*r orders:=order.pump(List,fcn(n){ (1.0 - scaleFactor)*dim*scaleFactor.pow(n) });
println(
- <<<
0'|<?xml version="1.0" standalone="no"?> <!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 1.1//EN"
"http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd">
<svg height="%d" width="%d" style="fill:blue" transform="translate(%d,%d) rotate(-18)"
version="1.1" xmlns="http://www.w3.org/2000/svg">|
- <<<
.fmt(dim*2,dim*2,dim,dim));
vertices:=sides.pump(List,fcn(s){ (1.0).toRectangular(tau*s/sides) }); // points on unit circle vx:=vertices.apply('wrap([(a,b)]v,x){ return(a*x,b*x) }, // scaled points orders[-1]*(1.0 - scaleFactor)); fmt:="%%0%d.%dB".fmt(sides,order).fmt; //-->%05.5B (leading zeros, 5 places, base 5) sides.pow(order).pump(Console.println,'wrap(i){
vector:=fmt(i).pump(List,vertices.get) // "00012"-->(vertices[0],..,vertices[2])
.zipWith(fcn([(a,b)]v,x){ return(a*x,b*x) },orders) // ((a,b)...)*x -->((ax,bx)...)
.reduce(fcn(vsum,v){ vsum[0]+=v[0]; vsum[1]+=v[1]; vsum },L(0.0, 0.0)); //-->(x,y)
pgon(vx.apply(fcn([(a,b)]v,c,d){ return(a+c,b+d) },vector.xplode()));
}); println("</svg>"); // 3,131 lines
fcn pgon(vertices){ // eg ( ((250,0),(248.595,1.93317),...), len 5
0'|<polygon points="%s"/>|.fmt(
vertices.pump(String,fcn(v){ "%.3f %.3f ".fmt(v.xplode()) }) )
}</lang>
- Output:
See this image. Displays fine in FireFox, in Chrome, it doesn't appear to be transformed so you only see part of the image.
zkl bbb > sierpinskiPentagon.zkl.svg $ wc sierpinskiPentagon.zkl.svg 3131 37519 314183 sierpinskiPentagon.zkl.svg