Sum of Array: Difference between revisions
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[ ( array size -- sum ) |
[ ( array size -- sum ) |
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>r 0 r> [ over i swap get |
>r 0 r> 0 [ over i swap array.get + ] countedLoop nip ] is sum-array |
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==[[UNIX Shell]]== |
==[[UNIX Shell]]== |
Revision as of 11:06, 11 September 2007
![Task](http://static.miraheze.org/rosettacodewiki/thumb/b/ba/Rcode-button-task-crushed.png/64px-Rcode-button-task-crushed.png)
You are encouraged to solve this task according to the task description, using any language you may know.
Compute the sum of the elements of an Array
4D
ARRAY INTEGER($list;0) For ($i;1;5) APPEND TO ARRAY($list;$i) End for $var:=0 For ($i;1;Size of array($list)) $var:=$var+$list{$i} End for
Ada
Int_Array : array(1..10) of Integer := (1,2,3,4,5,6,7,8,9,10); Sum : Integer := 0; for I in Int_Array'range loop Sum := Sum + Int_Array(I); end loop;
AppleScript
set array to {1, 2, 3, 4, 5} set product to 0 repeat with i in array -- very important -- list index starts at 1 not 0 set product to product + i end repeat
BASIC
10 REM Create an array with some test data in it 20 DIM ARRAY(5) 30 FOR I = 1 TO 5: READ ARRAY(I): NEXT I 40 DATA 1, 2, 3, 4, 5 50 REM Find the sum of elements in the array 60 SUM = 0 70 FOR I = 1 TO 5: SUM = SUM + ARRAY(I): NEXT I 80 PRINT "The sum is ";SUM
C++
Compiler: gcc 4.0.2
int main( int argc, char* argv[] ) { int list[] = { 1, 2, 3 } ; int sum = 0 ; for( int i = 0 ; i < 3 ; i++ ) { sum += list[i]; } }
Alternate
#include <numeric> int main( int argc, char* argv[] ) { int list[] = { 1, 2, 3 } ; std::accumulate(list, list + 3, 0); return 0; }
template alternative
template <typename T> T sum (const T *array, const unsigned n) { T accum = 0; for (unsigned i=0; i<n; i++) accum += array[i]; return accum; }
#include <iostream> using std::cout; using std::endl;
int main (void) { int aint[] = {1, 2, 3}; cout << sum(aint,3) << endl; float aflo[] = {1.1, 2.02, 3.003, 4.0004}; cout << sum(aflo,4) << endl; return 0; }
C#
int value = 0; int[] arg = { 1,2,3,4,5 }; int arg_length = arg.Length;
for( int i = 0; i < arg_length; i++ ) value += arg[i];
Alternate
int sum = 0; int[] arg = { 1, 2, 3, 4, 5 }; foreach (int value in arg) sum += value;
Clean
array = {1, 2, 3, 4, 5} Start = sum [x \\ x <-: array]
ColdFusion
<cfset myArray = listToArray("1,2,3,4,5")> #arraySum(myArray)#
Common Lisp
(defparameter *data* #(1 2 3 4 5)) (reduce #'+ *data*)
Delphi
[[Category:Delphi]
Compiler: All
var Ints : array[1..5] of integer = (1,2,3,4,5) ; i,Sum : integer = 0 ; begin for i := 1 to length(ints) do inc(sum,ints[i]) ; end;
E
pragma.enable("accumulator") accum 0 for x in [1,2,3,4,5] { _ + x }
Erlang
Using the standard libraries:
% create the list: L = lists:seq(1, 10).
% and compute its sum: S = lists:sum(L).
Or defining our own versions:
-module(list_sum). -export([sum_rec/1, sum_tail/1]).
% recursive definition: sum_rec([]) -> 0; sum_rec([Head|Tail]) -> Head + sum_rec(Tail).
% tail-recursive definition: sum_tail(L) -> sum_tail(L, 0). sum_tail([], Acc) -> Acc; sum_tail([Head|Tail], Acc) -> sum_tail(Tail, Head + Acc).
Forth
: sum ( addr cnt -- n ) 0 -rot cells bounds do i @ + cell +loop ;
FreeBASIC
dim array(4) as integer = { 1, 2, 3, 4, 5 }
dim sum as integer = 0 for index as integer = lbound(array) to ubound(array) sum += array(index) next
Haskell
let values = [1..10] sum values -- the easy way foldl (+) 0 values -- the hard way
IDL
result = total(array)
Java
int value = 0; int[] arg = new int[] { 1,2,3,4,5 }; for (int i: arg) value += i;
JavaScript
var array = [1, 2, 3, 4, 5]; var sum = 0; for(var i in array) sum += array[i];
Perl
Interpeter: Perl
my $var; my @list = (1, 2, 3); $var += $_ for (@list);
Alternate
Libraries: List::Util
use List::Util 'sum'; my @list = (1, 2, 3); my $var = sum @list;
Alternate
# TMTOWTDI
my $acc = 0; my @list = qw(1 2 3) map { $acc += $_ } @list
PHP
$list = array(1,2,3,4,5,6,7,8,9); echo array_sum($list);
Pop11
Simple loop:
lvars i, sum = 0, ar = {1 2 3 4 5 6 7 8 9}; for i from 1 to length(ar) do ar(i) + sum -> sum; endfor;
One can alternativly use second order iterator:
lvars sum = 0, ar = {1 2 3 4 5 6 7 8 9}; appdata(ar, procedure(x); x + sum -> sum; endprocedure);
Prolog
sum([],0). sum([H|T],X) :- sum(T,Y), X is H + Y.
test
:- sum([1,2,3,4,5,6,7,8,9],X). X =45;
Python
Interpeter: Python 2.5
total = sum([1, 2, 3, 4, 5, 6, 7, 8, 9])
Ruby
ary = [1,2,3,4,5] sum = ary.inject{|currentSum,element|currentSum+element} # => 15
Scala
val array = Array(1,2,3,4,5) val sum = array.foldLeft(0)(_ + _)
This is a shortcut for
val sum = array.foldLeft(0){(currentSum, element) => currentSum + element}
Seed7
const func integer: sumArray (in array integer: valueArray) is func result var integer: sum is 0; local var integer: value is 0; begin for value range valueArray do sum +:= value; end for; end func;
Call this function with:
writeln(sumArray([](1, 2, 3, 4, 5)));
Standard ML
val array = [1,2,3,4,5]; foldl op+ 0 array;
Tcl
Assuming the values are in a list named listname:
set result [expr [join $listname +]]
Toka
[ ( array size -- sum ) >r 0 r> 0 [ over i swap array.get + ] countedLoop nip ] is sum-array
UNIX Shell
Interpreter: NetBSD 3.0's ash
From an internal variable, $IFS delimited:
sum=0 list="1 2 3" for n in $list do sum="$(($sum + $n))" done echo $sum
From the argument list (ARGV):
sum=0 for n do sum="$(($sum + $n))" done echo $sum
From STDIN, one integer per line:
sum=0 while read n do sum="$(($sum + $n))" done echo $sum
Interpreter: GNU bash, version 3.2.0(1)-release (i386-unknown-freebsd6.1)
From variable:
LIST='20 20 2'; SUM=0; for i in $LIST; do SUM=$[$SUM + $i]; done; echo $SUM