Talk:Zeckendorf arithmetic: Difference between revisions
Content deleted Content added
No edit summary |
|||
Line 4: | Line 4: | ||
==Perl 6 error== |
==Perl 6 error== |
||
I get 10100 + 1010 = 101000, aka 11 + 7 = 18 which contradicts the Perl 6 output of 10100 +z 1010 = 100101 # addition. |
I get 10100 + 1010 = 101000, aka 11 + 7 = 18 which contradicts the Perl 6 output of 10100 +z 1010 = 100101 # addition. |
||
My output matches the first test of the tcl entry, which obviously also disagrees with the Perl output. |
|||
In turn the next line is 100101 -z 100 = 100010 # subtraction, which I read as 17-3 = 15. [[User:Petelomax|Pete Lomax]] ([[User talk:Petelomax|talk]]) 22:32, 21 August 2018 (UTC) |
In turn the next line is 100101 -z 100 = 100010 # subtraction, which I read as 17-3 = 15. [[User:Petelomax|Pete Lomax]] ([[User talk:Petelomax|talk]]) 22:32, 21 August 2018 (UTC) |
Revision as of 22:40, 21 August 2018
Spelling should be "arithmetic".
- Got it. --Mwn3d 14:45, 29 October 2012 (UTC)
Perl 6 error
I get 10100 + 1010 = 101000, aka 11 + 7 = 18 which contradicts the Perl 6 output of 10100 +z 1010 = 100101 # addition.
My output matches the first test of the tcl entry, which obviously also disagrees with the Perl output.
In turn the next line is 100101 -z 100 = 100010 # subtraction, which I read as 17-3 = 15. Pete Lomax (talk) 22:32, 21 August 2018 (UTC)